2(4x-5)+1=(-4x+5)+(7x-8)

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Solution for 2(4x-5)+1=(-4x+5)+(7x-8) equation: 



2(4x-5)+1=(-4x+5)+(7x-8)

We move all terms to the left:

2(4x-5)+1-((-4x+5)+(7x-8))=0

We multiply parentheses

8x-((-4x+5)+(7x-8))-10+1=0



We calculate terms in parentheses: -((-4x+5)+(7x-8)), so:

(-4x+5)+(7x-8)

We get rid of parentheses

-4x+7x+5-8

We add all the numbers together, and all the variables

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

8x-(3x-3)-9=0

We get rid of parentheses

8x-3x+3-9=0

We add all the numbers together, and all the variables

5x-6=0

We move all terms containing x to the left, all other terms to the right

5x=6

x=6/5

x=1+1/5

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