2(4x-5)+1=x-37

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Solution for 2(4x-5)+1=x-37 equation: 



2(4x-5)+1=x-37

We move all terms to the left:

2(4x-5)+1-(x-37)=0

We multiply parentheses

8x-(x-37)-10+1=0

We get rid of parentheses

8x-x+37-10+1=0

We add all the numbers together, and all the variables

7x+28=0

We move all terms containing x to the left, all other terms to the right

7x=-28

x=-28/7

x=-4

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