2(4x-5)+3=(4x-1)-3(x-5)

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Solution for 2(4x-5)+3=(4x-1)-3(x-5) equation: 



2(4x-5)+3=(4x-1)-3(x-5)

We move all terms to the left:

2(4x-5)+3-((4x-1)-3(x-5))=0

We multiply parentheses

8x-((4x-1)-3(x-5))-10+3=0



We calculate terms in parentheses: -((4x-1)-3(x-5)), so:

(4x-1)-3(x-5)

We multiply parentheses

(4x-1)-3x+15

We get rid of parentheses

4x-3x-1+15

We add all the numbers together, and all the variables

x+14

Back to the equation:

-(x+14)



We add all the numbers together, and all the variables

8x-(x+14)-7=0

We get rid of parentheses

8x-x-14-7=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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