2(4x-5)=40-2x

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Solution for 2(4x-5)=40-2x equation: 



2(4x-5)=40-2x

We move all terms to the left:

2(4x-5)-(40-2x)=0

We add all the numbers together, and all the variables

2(4x-5)-(-2x+40)=0

We multiply parentheses

8x-(-2x+40)-10=0

We get rid of parentheses

8x+2x-40-10=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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