2(4y+1)+3y=12

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Solution for 2(4y+1)+3y=12 equation: 



2(4y+1)+3y=12

We move all terms to the left:

2(4y+1)+3y-(12)=0

We add all the numbers together, and all the variables

3y+2(4y+1)-12=0

We multiply parentheses

3y+8y+2-12=0

We add all the numbers together, and all the variables

11y-10=0

We move all terms containing y to the left, all other terms to the right

11y=10

y=10/11

y=10/11

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