2(4y+1)=38y+2=3y5y=2

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Solution for 2(4y+1)=38y+2=3y5y=2 equation: 



2(4y+1)=38y+2=3y^5y=2

We move all terms to the left:

2(4y+1)-(38y+2)=0

We multiply parentheses

8y-(38y+2)+2=0

We get rid of parentheses

8y-38y-2+2=0

We add all the numbers together, and all the variables

-30y=0

y=0/-30

y=0

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