2(4y+1)=5(3-y)

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Solution for 2(4y+1)=5(3-y) equation: 



2(4y+1)=5(3-y)

We move all terms to the left:

2(4y+1)-(5(3-y))=0

We add all the numbers together, and all the variables

2(4y+1)-(5(-1y+3))=0

We multiply parentheses

8y-(5(-1y+3))+2=0



We calculate terms in parentheses: -(5(-1y+3)), so:

5(-1y+3)

We multiply parentheses

-5y+15

Back to the equation:

-(-5y+15)



We get rid of parentheses

8y+5y-15+2=0

We add all the numbers together, and all the variables

13y-13=0

We move all terms containing y to the left, all other terms to the right

13y=13

y=13/13

y=1

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