2(4y+2)=7y-3y+12

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Solution for 2(4y+2)=7y-3y+12 equation: 



2(4y+2)=7y-3y+12

We move all terms to the left:

2(4y+2)-(7y-3y+12)=0

We add all the numbers together, and all the variables

2(4y+2)-(4y+12)=0

We multiply parentheses

8y-(4y+12)+4=0

We get rid of parentheses

8y-4y-12+4=0

We add all the numbers together, and all the variables

4y-8=0

We move all terms containing y to the left, all other terms to the right

4y=8

y=8/4

y=2

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