2(4y+20)+12=(28y-44)-32

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Solution for 2(4y+20)+12=(28y-44)-32 equation:


Simplifying
2(4y + 20) + 12 = (28y + -44) + -32

Reorder the terms:
2(20 + 4y) + 12 = (28y + -44) + -32
(20 * 2 + 4y * 2) + 12 = (28y + -44) + -32
(40 + 8y) + 12 = (28y + -44) + -32

Reorder the terms:
40 + 12 + 8y = (28y + -44) + -32

Combine like terms: 40 + 12 = 52
52 + 8y = (28y + -44) + -32

Reorder the terms:
52 + 8y = (-44 + 28y) + -32

Remove parenthesis around (-44 + 28y)
52 + 8y = -44 + 28y + -32

Reorder the terms:
52 + 8y = -44 + -32 + 28y

Combine like terms: -44 + -32 = -76
52 + 8y = -76 + 28y

Solving
52 + 8y = -76 + 28y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-28y' to each side of the equation.
52 + 8y + -28y = -76 + 28y + -28y

Combine like terms: 8y + -28y = -20y
52 + -20y = -76 + 28y + -28y

Combine like terms: 28y + -28y = 0
52 + -20y = -76 + 0
52 + -20y = -76

Add '-52' to each side of the equation.
52 + -52 + -20y = -76 + -52

Combine like terms: 52 + -52 = 0
0 + -20y = -76 + -52
-20y = -76 + -52

Combine like terms: -76 + -52 = -128
-20y = -128

Divide each side by '-20'.
y = 6.4

Simplifying
y = 6.4

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