2(4y+5)+4y=2(y+20)

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Solution for 2(4y+5)+4y=2(y+20) equation: 


Simplifying
2(4y + 5) + 4y = 2(y + 20)

Reorder the terms:
2(5 + 4y) + 4y = 2(y + 20)
(5 * 2 + 4y * 2) + 4y = 2(y + 20)
(10 + 8y) + 4y = 2(y + 20)

Combine like terms: 8y + 4y = 12y
10 + 12y = 2(y + 20)

Reorder the terms:
10 + 12y = 2(20 + y)
10 + 12y = (20 * 2 + y * 2)
10 + 12y = (40 + 2y)

Solving
10 + 12y = 40 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
10 + 12y + -2y = 40 + 2y + -2y

Combine like terms: 12y + -2y = 10y
10 + 10y = 40 + 2y + -2y

Combine like terms: 2y + -2y = 0
10 + 10y = 40 + 0
10 + 10y = 40

Add '-10' to each side of the equation.
10 + -10 + 10y = 40 + -10

Combine like terms: 10 + -10 = 0
0 + 10y = 40 + -10
10y = 40 + -10

Combine like terms: 40 + -10 = 30
10y = 30

Divide each side by '10'.
y = 3

Simplifying
y = 3

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