2(4y-)=40

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Solution for 2(4y-)=40 equation: 



2(4y-)=40

We move all terms to the left:

2(4y-)-(40)=0

We add all the numbers together, and all the variables

2(+4y)-40=0

We multiply parentheses

8y-40=0

We move all terms containing y to the left, all other terms to the right

8y=40

y=40/8

y=5

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