2(4y-2)=-20

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Solution for 2(4y-2)=-20 equation: 



2(4y-2)=-20

We move all terms to the left:

2(4y-2)-(-20)=0

We add all the numbers together, and all the variables

2(4y-2)+20=0

We multiply parentheses

8y-4+20=0

We add all the numbers together, and all the variables

8y+16=0

We move all terms containing y to the left, all other terms to the right

8y=-16

y=-16/8

y=-2

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