2(4y-2)=10

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Solution for 2(4y-2)=10 equation: 



2(4y-2)=10

We move all terms to the left:

2(4y-2)-(10)=0

We multiply parentheses

8y-4-10=0

We add all the numbers together, and all the variables

8y-14=0

We move all terms containing y to the left, all other terms to the right

8y=14

y=14/8

y=1+3/4

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