2(4y-3)+2y=8y-6y+2y=10y-6

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Solution for 2(4y-3)+2y=8y-6y+2y=10y-6 equation: 



2(4y-3)+2y=8y-6y+2y=10y-6

We move all terms to the left:

2(4y-3)+2y-(8y-6y+2y)=0

We add all the numbers together, and all the variables

2(4y-3)+2y-(+4y)=0

We add all the numbers together, and all the variables

2y+2(4y-3)-(+4y)=0

We multiply parentheses

2y+8y-(+4y)-6=0

We get rid of parentheses

2y+8y-4y-6=0

We add all the numbers together, and all the variables

6y-6=0

We move all terms containing y to the left, all other terms to the right

6y=6

y=6/6

y=1

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