2(4z+3)=4(2z-6)+15

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Solution for 2(4z+3)=4(2z-6)+15 equation: 



2(4z+3)=4(2z-6)+15

We move all terms to the left:

2(4z+3)-(4(2z-6)+15)=0

We multiply parentheses

8z-(4(2z-6)+15)+6=0



We calculate terms in parentheses: -(4(2z-6)+15), so:

4(2z-6)+15

We multiply parentheses

8z-24+15

We add all the numbers together, and all the variables

8z-9

Back to the equation:

-(8z-9)



We get rid of parentheses

8z-8z+9+6=0

We add all the numbers together, and all the variables

15!=0

There is no solution for this equation

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