2(4z-)=3(z+2)

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Solution for 2(4z-)=3(z+2) equation: 



2(4z-)=3(z+2)

We move all terms to the left:

2(4z-)-(3(z+2))=0

We add all the numbers together, and all the variables

2(+4z)-(3(z+2))=0

We multiply parentheses

8z-(3(z+2))=0



We calculate terms in parentheses: -(3(z+2)), so:

3(z+2)

We multiply parentheses

3z+6

Back to the equation:

-(3z+6)



We get rid of parentheses

8z-3z-6=0

We add all the numbers together, and all the variables

5z-6=0

We move all terms containing z to the left, all other terms to the right

5z=6

z=6/5

z=1+1/5

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