2(4z-1)-2(z+4)=3(z+1)

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Solution for 2(4z-1)-2(z+4)=3(z+1) equation:


Simplifying
2(4z + -1) + -2(z + 4) = 3(z + 1)

Reorder the terms:
2(-1 + 4z) + -2(z + 4) = 3(z + 1)
(-1 * 2 + 4z * 2) + -2(z + 4) = 3(z + 1)
(-2 + 8z) + -2(z + 4) = 3(z + 1)

Reorder the terms:
-2 + 8z + -2(4 + z) = 3(z + 1)
-2 + 8z + (4 * -2 + z * -2) = 3(z + 1)
-2 + 8z + (-8 + -2z) = 3(z + 1)

Reorder the terms:
-2 + -8 + 8z + -2z = 3(z + 1)

Combine like terms: -2 + -8 = -10
-10 + 8z + -2z = 3(z + 1)

Combine like terms: 8z + -2z = 6z
-10 + 6z = 3(z + 1)

Reorder the terms:
-10 + 6z = 3(1 + z)
-10 + 6z = (1 * 3 + z * 3)
-10 + 6z = (3 + 3z)

Solving
-10 + 6z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-10 + 6z + -3z = 3 + 3z + -3z

Combine like terms: 6z + -3z = 3z
-10 + 3z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-10 + 3z = 3 + 0
-10 + 3z = 3

Add '10' to each side of the equation.
-10 + 10 + 3z = 3 + 10

Combine like terms: -10 + 10 = 0
0 + 3z = 3 + 10
3z = 3 + 10

Combine like terms: 3 + 10 = 13
3z = 13

Divide each side by '3'.
z = 4.333333333

Simplifying
z = 4.333333333

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