2(4z-1)-3(2+4)=3(z+1)

Solution for 2(4z-1)-3(2+4)=3(z+1) equation:

Simplifying
2(4z + -1) + -3(2 + 4) = 3(z + 1)

Reorder the terms:
2(-1 + 4z) + -3(2 + 4) = 3(z + 1)
(-1 * 2 + 4z * 2) + -3(2 + 4) = 3(z + 1)
(-2 + 8z) + -3(2 + 4) = 3(z + 1)

Combine like terms: 2 + 4 = 6
-2 + 8z + -3(6) = 3(z + 1)

Multiply -3 * 6
-2 + 8z + -18 = 3(z + 1)

Reorder the terms:
-2 + -18 + 8z = 3(z + 1)

Combine like terms: -2 + -18 = -20
-20 + 8z = 3(z + 1)

Reorder the terms:
-20 + 8z = 3(1 + z)
-20 + 8z = (1 * 3 + z * 3)
-20 + 8z = (3 + 3z)

Solving
-20 + 8z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-20 + 8z + -3z = 3 + 3z + -3z

Combine like terms: 8z + -3z = 5z
-20 + 5z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-20 + 5z = 3 + 0
-20 + 5z = 3

Add '20' to each side of the equation.
-20 + 20 + 5z = 3 + 20

Combine like terms: -20 + 20 = 0
0 + 5z = 3 + 20
5z = 3 + 20

Combine like terms: 3 + 20 = 23
5z = 23

Divide each side by '5'.
z = 4.6

Simplifying
z = 4.6