2(4z-1)-3(z+1)=2(z+1)

Solution for 2(4z-1)-3(z+1)=2(z+1) equation:

Simplifying
2(4z + -1) + -3(z + 1) = 2(z + 1)

Reorder the terms:
2(-1 + 4z) + -3(z + 1) = 2(z + 1)
(-1 * 2 + 4z * 2) + -3(z + 1) = 2(z + 1)
(-2 + 8z) + -3(z + 1) = 2(z + 1)

Reorder the terms:
-2 + 8z + -3(1 + z) = 2(z + 1)
-2 + 8z + (1 * -3 + z * -3) = 2(z + 1)
-2 + 8z + (-3 + -3z) = 2(z + 1)

Reorder the terms:
-2 + -3 + 8z + -3z = 2(z + 1)

Combine like terms: -2 + -3 = -5
-5 + 8z + -3z = 2(z + 1)

Combine like terms: 8z + -3z = 5z
-5 + 5z = 2(z + 1)

Reorder the terms:
-5 + 5z = 2(1 + z)
-5 + 5z = (1 * 2 + z * 2)
-5 + 5z = (2 + 2z)

Solving
-5 + 5z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-5 + 5z + -2z = 2 + 2z + -2z

Combine like terms: 5z + -2z = 3z
-5 + 3z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-5 + 3z = 2 + 0
-5 + 3z = 2

Add '5' to each side of the equation.
-5 + 5 + 3z = 2 + 5

Combine like terms: -5 + 5 = 0
0 + 3z = 2 + 5
3z = 2 + 5

Combine like terms: 2 + 5 = 7
3z = 7

Divide each side by '3'.
z = 2.333333333

Simplifying
z = 2.333333333