2(4z-1)-3(z+2)=2(z+1)

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Solution for 2(4z-1)-3(z+2)=2(z+1) equation:


Simplifying
2(4z + -1) + -3(z + 2) = 2(z + 1)

Reorder the terms:
2(-1 + 4z) + -3(z + 2) = 2(z + 1)
(-1 * 2 + 4z * 2) + -3(z + 2) = 2(z + 1)
(-2 + 8z) + -3(z + 2) = 2(z + 1)

Reorder the terms:
-2 + 8z + -3(2 + z) = 2(z + 1)
-2 + 8z + (2 * -3 + z * -3) = 2(z + 1)
-2 + 8z + (-6 + -3z) = 2(z + 1)

Reorder the terms:
-2 + -6 + 8z + -3z = 2(z + 1)

Combine like terms: -2 + -6 = -8
-8 + 8z + -3z = 2(z + 1)

Combine like terms: 8z + -3z = 5z
-8 + 5z = 2(z + 1)

Reorder the terms:
-8 + 5z = 2(1 + z)
-8 + 5z = (1 * 2 + z * 2)
-8 + 5z = (2 + 2z)

Solving
-8 + 5z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-8 + 5z + -2z = 2 + 2z + -2z

Combine like terms: 5z + -2z = 3z
-8 + 3z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-8 + 3z = 2 + 0
-8 + 3z = 2

Add '8' to each side of the equation.
-8 + 8 + 3z = 2 + 8

Combine like terms: -8 + 8 = 0
0 + 3z = 2 + 8
3z = 2 + 8

Combine like terms: 2 + 8 = 10
3z = 10

Divide each side by '3'.
z = 3.333333333

Simplifying
z = 3.333333333

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