2(4z-1)-3(z+4)=2(z+1)

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Solution for 2(4z-1)-3(z+4)=2(z+1) equation:


Simplifying
2(4z + -1) + -3(z + 4) = 2(z + 1)

Reorder the terms:
2(-1 + 4z) + -3(z + 4) = 2(z + 1)
(-1 * 2 + 4z * 2) + -3(z + 4) = 2(z + 1)
(-2 + 8z) + -3(z + 4) = 2(z + 1)

Reorder the terms:
-2 + 8z + -3(4 + z) = 2(z + 1)
-2 + 8z + (4 * -3 + z * -3) = 2(z + 1)
-2 + 8z + (-12 + -3z) = 2(z + 1)

Reorder the terms:
-2 + -12 + 8z + -3z = 2(z + 1)

Combine like terms: -2 + -12 = -14
-14 + 8z + -3z = 2(z + 1)

Combine like terms: 8z + -3z = 5z
-14 + 5z = 2(z + 1)

Reorder the terms:
-14 + 5z = 2(1 + z)
-14 + 5z = (1 * 2 + z * 2)
-14 + 5z = (2 + 2z)

Solving
-14 + 5z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-14 + 5z + -2z = 2 + 2z + -2z

Combine like terms: 5z + -2z = 3z
-14 + 3z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-14 + 3z = 2 + 0
-14 + 3z = 2

Add '14' to each side of the equation.
-14 + 14 + 3z = 2 + 14

Combine like terms: -14 + 14 = 0
0 + 3z = 2 + 14
3z = 2 + 14

Combine like terms: 2 + 14 = 16
3z = 16

Divide each side by '3'.
z = 5.333333333

Simplifying
z = 5.333333333

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