2(4z-1)-3(z+4)=3(z+1)

Solution for 2(4z-1)-3(z+4)=3(z+1) equation:

Simplifying
2(4z + -1) + -3(z + 4) = 3(z + 1)

Reorder the terms:
2(-1 + 4z) + -3(z + 4) = 3(z + 1)
(-1 * 2 + 4z * 2) + -3(z + 4) = 3(z + 1)
(-2 + 8z) + -3(z + 4) = 3(z + 1)

Reorder the terms:
-2 + 8z + -3(4 + z) = 3(z + 1)
-2 + 8z + (4 * -3 + z * -3) = 3(z + 1)
-2 + 8z + (-12 + -3z) = 3(z + 1)

Reorder the terms:
-2 + -12 + 8z + -3z = 3(z + 1)

Combine like terms: -2 + -12 = -14
-14 + 8z + -3z = 3(z + 1)

Combine like terms: 8z + -3z = 5z
-14 + 5z = 3(z + 1)

Reorder the terms:
-14 + 5z = 3(1 + z)
-14 + 5z = (1 * 3 + z * 3)
-14 + 5z = (3 + 3z)

Solving
-14 + 5z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-14 + 5z + -3z = 3 + 3z + -3z

Combine like terms: 5z + -3z = 2z
-14 + 2z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-14 + 2z = 3 + 0
-14 + 2z = 3

Add '14' to each side of the equation.
-14 + 14 + 2z = 3 + 14

Combine like terms: -14 + 14 = 0
0 + 2z = 3 + 14
2z = 3 + 14

Combine like terms: 3 + 14 = 17
2z = 17

Divide each side by '2'.
z = 8.5

Simplifying
z = 8.5