2(4z-1)=3(2z+2)

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Solution for 2(4z-1)=3(2z+2) equation: 



2(4z-1)=3(2z+2)

We move all terms to the left:

2(4z-1)-(3(2z+2))=0

We multiply parentheses

8z-(3(2z+2))-2=0



We calculate terms in parentheses: -(3(2z+2)), so:

3(2z+2)

We multiply parentheses

6z+6

Back to the equation:

-(6z+6)



We get rid of parentheses

8z-6z-6-2=0

We add all the numbers together, and all the variables

2z-8=0

We move all terms containing z to the left, all other terms to the right

2z=8

z=8/2

z=4

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