2(4z-1)=3z(z+2)

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Solution for 2(4z-1)=3z(z+2) equation:



2(4z-1)=3z(z+2)
We move all terms to the left:
2(4z-1)-(3z(z+2))=0
We multiply parentheses
8z-(3z(z+2))-2=0
We calculate terms in parentheses: -(3z(z+2)), so:
3z(z+2)
We multiply parentheses
3z^2+6z
Back to the equation:
-(3z^2+6z)
We get rid of parentheses
-3z^2+8z-6z-2=0
We add all the numbers together, and all the variables
-3z^2+2z-2=0
a = -3; b = 2; c = -2;
Δ = b2-4ac
Δ = 22-4·(-3)·(-2)
Δ = -20
Delta is less than zero, so there is no solution for the equation

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