2(4z-1)=6+3z

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Solution for 2(4z-1)=6+3z equation: 



2(4z-1)=6+3z

We move all terms to the left:

2(4z-1)-(6+3z)=0

We add all the numbers together, and all the variables

2(4z-1)-(3z+6)=0

We multiply parentheses

8z-(3z+6)-2=0

We get rid of parentheses

8z-3z-6-2=0

We add all the numbers together, and all the variables

5z-8=0

We move all terms containing z to the left, all other terms to the right

5z=8

z=8/5

z=1+3/5

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