2(4z-10)=5z-32

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Solution for 2(4z-10)=5z-32 equation:


Simplifying
2(4z + -10) = 5z + -32

Reorder the terms:
2(-10 + 4z) = 5z + -32
(-10 * 2 + 4z * 2) = 5z + -32
(-20 + 8z) = 5z + -32

Reorder the terms:
-20 + 8z = -32 + 5z

Solving
-20 + 8z = -32 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-20 + 8z + -5z = -32 + 5z + -5z

Combine like terms: 8z + -5z = 3z
-20 + 3z = -32 + 5z + -5z

Combine like terms: 5z + -5z = 0
-20 + 3z = -32 + 0
-20 + 3z = -32

Add '20' to each side of the equation.
-20 + 20 + 3z = -32 + 20

Combine like terms: -20 + 20 = 0
0 + 3z = -32 + 20
3z = -32 + 20

Combine like terms: -32 + 20 = -12
3z = -12

Divide each side by '3'.
z = -4

Simplifying
z = -4

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