2(4z-3)=-2(2z+15)

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Solution for 2(4z-3)=-2(2z+15) equation: 



2(4z-3)=-2(2z+15)

We move all terms to the left:

2(4z-3)-(-2(2z+15))=0

We multiply parentheses

8z-(-2(2z+15))-6=0



We calculate terms in parentheses: -(-2(2z+15)), so:

-2(2z+15)

We multiply parentheses

-4z-30

Back to the equation:

-(-4z-30)



We get rid of parentheses

8z+4z+30-6=0

We add all the numbers together, and all the variables

12z+24=0

We move all terms containing z to the left, all other terms to the right

12z=-24

z=-24/12

z=-2

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