2(4z-8)=2z+26

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Solution for 2(4z-8)=2z+26 equation: 



2(4z-8)=2z+26

We move all terms to the left:

2(4z-8)-(2z+26)=0

We multiply parentheses

8z-(2z+26)-16=0

We get rid of parentheses

8z-2z-26-16=0

We add all the numbers together, and all the variables

6z-42=0

We move all terms containing z to the left, all other terms to the right

6z=42

z=42/6

z=7

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