2(5)+2=12+3x+4(2x-5)-6x

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Solution for 2(5)+2=12+3x+4(2x-5)-6x equation: 



2(5)+2=12+3x+4(2x-5)-6x

We move all terms to the left:

2(5)+2-(12+3x+4(2x-5)-6x)=0

We add all the numbers together, and all the variables

-(12+3x+4(2x-5)-6x)+27=0



We calculate terms in parentheses: -(12+3x+4(2x-5)-6x), so:

12+3x+4(2x-5)-6x

determiningTheFunctionDomain
3x+4(2x-5)-6x+12

We add all the numbers together, and all the variables

-3x+4(2x-5)+12

We multiply parentheses

-3x+8x-20+12

We add all the numbers together, and all the variables

5x-8

Back to the equation:

-(5x-8)



We get rid of parentheses

-5x+8+27=0

We add all the numbers together, and all the variables

-5x+35=0

We move all terms containing x to the left, all other terms to the right

-5x=-35

x=-35/-5

x=+7

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