2(5+b)=3(b-2)

Solution for 2(5+b)=3(b-2) equation:

Simplifying
2(5 + b) = 3(b + -2)
(5 * 2 + b * 2) = 3(b + -2)
(10 + 2b) = 3(b + -2)

Reorder the terms:
10 + 2b = 3(-2 + b)
10 + 2b = (-2 * 3 + b * 3)
10 + 2b = (-6 + 3b)

Solving
10 + 2b = -6 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
10 + 2b + -3b = -6 + 3b + -3b

Combine like terms: 2b + -3b = -1b
10 + -1b = -6 + 3b + -3b

Combine like terms: 3b + -3b = 0
10 + -1b = -6 + 0
10 + -1b = -6

Add '-10' to each side of the equation.
10 + -10 + -1b = -6 + -10

Combine like terms: 10 + -10 = 0
0 + -1b = -6 + -10
-1b = -6 + -10

Combine like terms: -6 + -10 = -16
-1b = -16

Divide each side by '-1'.
b = 16

Simplifying
b = 16