2(5-2)z=20-2(z-1)

Solution for 2(5-2)z=20-2(z-1) equation:

2(5-2)z=20-2(z-1)

We move all terms to the left:

2(5-2)z-(20-2(z-1))=0

We add all the numbers together, and all the variables

23z-(20-2(z-1))=0


We calculate terms in parentheses: -(20-2(z-1)), so:

20-2(z-1)

determiningTheFunctionDomain
-2(z-1)+20

We multiply parentheses

-2z+2+20

We add all the numbers together, and all the variables

-2z+22

Back to the equation:

-(-2z+22)


We get rid of parentheses

23z+2z-22=0

We add all the numbers together, and all the variables

25z-22=0

We move all terms containing z to the left, all other terms to the right

25z=22

z=22/25

z=22/25