2(5-2)z=20-2(z-1)

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Solution for 2(5-2)z=20-2(z-1) equation:



2(5-2)z=20-2(z-1)
We move all terms to the left:
2(5-2)z-(20-2(z-1))=0
We add all the numbers together, and all the variables
23z-(20-2(z-1))=0
We calculate terms in parentheses: -(20-2(z-1)), so:
20-2(z-1)
determiningTheFunctionDomain -2(z-1)+20
We multiply parentheses
-2z+2+20
We add all the numbers together, and all the variables
-2z+22
Back to the equation:
-(-2z+22)
We get rid of parentheses
23z+2z-22=0
We add all the numbers together, and all the variables
25z-22=0
We move all terms containing z to the left, all other terms to the right
25z=22
z=22/25
z=22/25

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