2(5-2c)+3c=5(c+2)+5

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Solution for 2(5-2c)+3c=5(c+2)+5 equation: 


Simplifying
2(5 + -2c) + 3c = 5(c + 2) + 5
(5 * 2 + -2c * 2) + 3c = 5(c + 2) + 5
(10 + -4c) + 3c = 5(c + 2) + 5

Combine like terms: -4c + 3c = -1c
10 + -1c = 5(c + 2) + 5

Reorder the terms:
10 + -1c = 5(2 + c) + 5
10 + -1c = (2 * 5 + c * 5) + 5
10 + -1c = (10 + 5c) + 5

Reorder the terms:
10 + -1c = 10 + 5 + 5c

Combine like terms: 10 + 5 = 15
10 + -1c = 15 + 5c

Solving
10 + -1c = 15 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
10 + -1c + -5c = 15 + 5c + -5c

Combine like terms: -1c + -5c = -6c
10 + -6c = 15 + 5c + -5c

Combine like terms: 5c + -5c = 0
10 + -6c = 15 + 0
10 + -6c = 15

Add '-10' to each side of the equation.
10 + -10 + -6c = 15 + -10

Combine like terms: 10 + -10 = 0
0 + -6c = 15 + -10
-6c = 15 + -10

Combine like terms: 15 + -10 = 5
-6c = 5

Divide each side by '-6'.
c = -0.8333333333

Simplifying
c = -0.8333333333

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