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2(5-2x)=3(2x+1)
We move all terms to the left:
2(5-2x)-(3(2x+1))=0
We add all the numbers together, and all the variables
2(-2x+5)-(3(2x+1))=0
We multiply parentheses
-4x-(3(2x+1))+10=0
We calculate terms in parentheses: -(3(2x+1)), so:We get rid of parentheses
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
-4x-6x-3+10=0
We add all the numbers together, and all the variables
-10x+7=0
We move all terms containing x to the left, all other terms to the right
-10x=-7
x=-7/-10
x=7/10
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