2(5-2x-5x)=19-5(2x+5)

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Solution for 2(5-2x-5x)=19-5(2x+5) equation: 



2(5-2x-5x)=19-5(2x+5)

We move all terms to the left:

2(5-2x-5x)-(19-5(2x+5))=0

We add all the numbers together, and all the variables

2(-7x+5)-(19-5(2x+5))=0

We multiply parentheses

-14x-(19-5(2x+5))+10=0



We calculate terms in parentheses: -(19-5(2x+5)), so:

19-5(2x+5)

determiningTheFunctionDomain
-5(2x+5)+19

We multiply parentheses

-10x-25+19

We add all the numbers together, and all the variables

-10x-6

Back to the equation:

-(-10x-6)



We get rid of parentheses

-14x+10x+6+10=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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