2(5-2z)=20(z-1)

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Solution for 2(5-2z)=20(z-1) equation: 



2(5-2z)=20(z-1)

We move all terms to the left:

2(5-2z)-(20(z-1))=0

We add all the numbers together, and all the variables

2(-2z+5)-(20(z-1))=0

We multiply parentheses

-4z-(20(z-1))+10=0



We calculate terms in parentheses: -(20(z-1)), so:

20(z-1)

We multiply parentheses

20z-20

Back to the equation:

-(20z-20)



We get rid of parentheses

-4z-20z+20+10=0

We add all the numbers together, and all the variables

-24z+30=0

We move all terms containing z to the left, all other terms to the right

-24z=-30

z=-30/-24

z=1+1/4

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