2(5-2z)=20-(z-1)

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Solution for 2(5-2z)=20-(z-1) equation: 



2(5-2z)=20-(z-1)

We move all terms to the left:

2(5-2z)-(20-(z-1))=0

We add all the numbers together, and all the variables

2(-2z+5)-(20-(z-1))=0

We multiply parentheses

-4z-(20-(z-1))+10=0



We calculate terms in parentheses: -(20-(z-1)), so:

20-(z-1)

determiningTheFunctionDomain
-(z-1)+20

We get rid of parentheses

-z+1+20

We add all the numbers together, and all the variables

-1z+21

Back to the equation:

-(-1z+21)



We get rid of parentheses

-4z+1z-21+10=0

We add all the numbers together, and all the variables

-3z-11=0

We move all terms containing z to the left, all other terms to the right

-3z=11

z=11/-3

z=-3+2/3

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