2(5-3b)=6(7+b)+16

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Solution for 2(5-3b)=6(7+b)+16 equation:



2(5-3b)=6(7+b)+16
We move all terms to the left:
2(5-3b)-(6(7+b)+16)=0
We add all the numbers together, and all the variables
2(-3b+5)-(6(b+7)+16)=0
We multiply parentheses
-6b-(6(b+7)+16)+10=0
We calculate terms in parentheses: -(6(b+7)+16), so:
6(b+7)+16
We multiply parentheses
6b+42+16
We add all the numbers together, and all the variables
6b+58
Back to the equation:
-(6b+58)
We get rid of parentheses
-6b-6b-58+10=0
We add all the numbers together, and all the variables
-12b-48=0
We move all terms containing b to the left, all other terms to the right
-12b=48
b=48/-12
b=-4

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