2(5-3x)=10-10(x-2)

Solution for 2(5-3x)=10-10(x-2) equation:

2(5-3x)=10-10(x-2)

We move all terms to the left:

2(5-3x)-(10-10(x-2))=0

We add all the numbers together, and all the variables

2(-3x+5)-(10-10(x-2))=0

We multiply parentheses

-6x-(10-10(x-2))+10=0


We calculate terms in parentheses: -(10-10(x-2)), so:

10-10(x-2)

determiningTheFunctionDomain
-10(x-2)+10

We multiply parentheses

-10x+20+10

We add all the numbers together, and all the variables

-10x+30

Back to the equation:

-(-10x+30)


We get rid of parentheses

-6x+10x-30+10=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5