2(5-D)/7+4(6+D)/10=7d+7

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Solution for 2(5-D)/7+4(6+D)/10=7d+7 equation: 



2(5-)/7+4(6+)/10=7D+7

We move all terms to the left:

2(5-)/7+4(6+)/10-(7D+7)=0

We add all the numbers together, and all the variables

-(7D+7)+20/7+40/10=0

We add all the numbers together, and all the variables

-(7D+7)+4+20/7=0

We get rid of parentheses

-7D-7+4+20/7=0

We multiply all the terms by the denominator


-7D*7+20-7*7+4*7=0

We add all the numbers together, and all the variables

-7D*7-1=0

Wy multiply elements

-49D-1=0

We move all terms containing D to the left, all other terms to the right

-49D=1

D=1/-49

D=-1/49

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