2(5-b)+6b=b+22

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Solution for 2(5-b)+6b=b+22 equation: 



2(5-b)+6b=b+22

We move all terms to the left:

2(5-b)+6b-(b+22)=0

We add all the numbers together, and all the variables

2(-1b+5)+6b-(b+22)=0

We add all the numbers together, and all the variables

6b+2(-1b+5)-(b+22)=0

We multiply parentheses

6b-2b-(b+22)+10=0

We get rid of parentheses

6b-2b-b-22+10=0

We add all the numbers together, and all the variables

3b-12=0

We move all terms containing b to the left, all other terms to the right

3b=12

b=12/3

b=4

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