2(5-m)+22=2(2m-7)-20

Solution for 2(5-m)+22=2(2m-7)-20 equation:

2(5-m)+22=2(2m-7)-20

We move all terms to the left:

2(5-m)+22-(2(2m-7)-20)=0

We add all the numbers together, and all the variables

2(-1m+5)-(2(2m-7)-20)+22=0

We multiply parentheses

-2m-(2(2m-7)-20)+10+22=0


We calculate terms in parentheses: -(2(2m-7)-20), so:

2(2m-7)-20

We multiply parentheses

4m-14-20

We add all the numbers together, and all the variables

4m-34

Back to the equation:

-(4m-34)


We add all the numbers together, and all the variables

-2m-(4m-34)+32=0

We get rid of parentheses

-2m-4m+34+32=0

We add all the numbers together, and all the variables

-6m+66=0

We move all terms containing m to the left, all other terms to the right

-6m=-66

m=-66/-6

m=+11