2(5-t)+6t=t+22t

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Solution for 2(5-t)+6t=t+22t equation:



2(5-t)+6t=t+22t
We move all terms to the left:
2(5-t)+6t-(t+22t)=0
We add all the numbers together, and all the variables
2(-1t+5)+6t-(+23t)=0
We add all the numbers together, and all the variables
6t+2(-1t+5)-(+23t)=0
We multiply parentheses
6t-2t-(+23t)+10=0
We get rid of parentheses
6t-2t-23t+10=0
We add all the numbers together, and all the variables
-19t+10=0
We move all terms containing t to the left, all other terms to the right
-19t=-10
t=-10/-19
t=10/19

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