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2(5-x)-(x+2)=3+7(x-5)
We move all terms to the left:
2(5-x)-(x+2)-(3+7(x-5))=0
We add all the numbers together, and all the variables
2(-1x+5)-(x+2)-(3+7(x-5))=0
We multiply parentheses
-2x-(x+2)-(3+7(x-5))+10=0
We get rid of parentheses
-2x-x-(3+7(x-5))-2+10=0
We calculate terms in parentheses: -(3+7(x-5)), so:We add all the numbers together, and all the variables
3+7(x-5)
determiningTheFunctionDomain 7(x-5)+3
We multiply parentheses
7x-35+3
We add all the numbers together, and all the variables
7x-32
Back to the equation:
-(7x-32)
-3x-(7x-32)+8=0
We get rid of parentheses
-3x-7x+32+8=0
We add all the numbers together, and all the variables
-10x+40=0
We move all terms containing x to the left, all other terms to the right
-10x=-40
x=-40/-10
x=+4
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