2(5-x)-4(x-3)=6(2-x)+10

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Solution for 2(5-x)-4(x-3)=6(2-x)+10 equation: 



2(5-x)-4(x-3)=6(2-x)+10

We move all terms to the left:

2(5-x)-4(x-3)-(6(2-x)+10)=0

We add all the numbers together, and all the variables

2(-1x+5)-4(x-3)-(6(-1x+2)+10)=0

We multiply parentheses

-2x-4x-(6(-1x+2)+10)+10+12=0



We calculate terms in parentheses: -(6(-1x+2)+10), so:

6(-1x+2)+10

We multiply parentheses

-6x+12+10

We add all the numbers together, and all the variables

-6x+22

Back to the equation:

-(-6x+22)



We add all the numbers together, and all the variables

-6x-(-6x+22)+22=0

We get rid of parentheses

-6x+6x-22+22=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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