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2(5-x)-5x-5x=3-2(2+x)
We move all terms to the left:
2(5-x)-5x-5x-(3-2(2+x))=0
We add all the numbers together, and all the variables
2(-1x+5)-5x-5x-(3-2(x+2))=0
We add all the numbers together, and all the variables
-10x+2(-1x+5)-(3-2(x+2))=0
We multiply parentheses
-10x-2x-(3-2(x+2))+10=0
We calculate terms in parentheses: -(3-2(x+2)), so:We add all the numbers together, and all the variables
3-2(x+2)
determiningTheFunctionDomain -2(x+2)+3
We multiply parentheses
-2x-4+3
We add all the numbers together, and all the variables
-2x-1
Back to the equation:
-(-2x-1)
-12x-(-2x-1)+10=0
We get rid of parentheses
-12x+2x+1+10=0
We add all the numbers together, and all the variables
-10x+11=0
We move all terms containing x to the left, all other terms to the right
-10x=-11
x=-11/-10
x=1+1/10
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