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2(5-x0)-(-2)(x-3)=-(3x-4)
We move all terms to the left:
2(5-x0)-(-2)(x-3)-(-(3x-4))=0
We add all the numbers together, and all the variables
2(-1x+5)-(-2)(x-3)-(-(3x-4))=0
We multiply parentheses
-2x-(-2)(x-3)-(-(3x-4))+10=0
We multiply parentheses ..
-2x-(-2x+6)-(-(3x-4))+10=0
We calculate terms in parentheses: -(-(3x-4)), so:We get rid of parentheses
-(3x-4)
We get rid of parentheses
-3x+4
Back to the equation:
-(-3x+4)
-2x+2x+3x-6-4+10=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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