2(50-2y-.5z)+4y+z=100

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Solution for 2(50-2y-.5z)+4y+z=100 equation: 


Simplifying
2(50 + -2y + -0.5z) + 4y + z = 100
(50 * 2 + -2y * 2 + -0.5z * 2) + 4y + z = 100
(100 + -4y + -1z) + 4y + z = 100

Reorder the terms:
100 + -4y + 4y + -1z + z = 100

Combine like terms: -4y + 4y = 0
100 + 0 + -1z + z = 100
100 + -1z + z = 100

Combine like terms: -1z + z = 0
100 + 0 = 100
100 = 100

Add '-100' to each side of the equation.
100 + -100 = 100 + -100

Combine like terms: 100 + -100 = 0
0 = 100 + -100

Combine like terms: 100 + -100 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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