2(56+2)+2c=3(2c+3)+7

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Solution for 2(56+2)+2c=3(2c+3)+7 equation: 


Simplifying
2(56 + 2) + 2c = 3(2c + 3) + 7

Combine like terms: 56 + 2 = 58
2(58) + 2c = 3(2c + 3) + 7

Multiply 2 * 58
116 + 2c = 3(2c + 3) + 7

Reorder the terms:
116 + 2c = 3(3 + 2c) + 7
116 + 2c = (3 * 3 + 2c * 3) + 7
116 + 2c = (9 + 6c) + 7

Reorder the terms:
116 + 2c = 9 + 7 + 6c

Combine like terms: 9 + 7 = 16
116 + 2c = 16 + 6c

Solving
116 + 2c = 16 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
116 + 2c + -6c = 16 + 6c + -6c

Combine like terms: 2c + -6c = -4c
116 + -4c = 16 + 6c + -6c

Combine like terms: 6c + -6c = 0
116 + -4c = 16 + 0
116 + -4c = 16

Add '-116' to each side of the equation.
116 + -116 + -4c = 16 + -116

Combine like terms: 116 + -116 = 0
0 + -4c = 16 + -116
-4c = 16 + -116

Combine like terms: 16 + -116 = -100
-4c = -100

Divide each side by '-4'.
c = 25

Simplifying
c = 25

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