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2(5a+1)+2=3(a-1)
We move all terms to the left:
2(5a+1)+2-(3(a-1))=0
We multiply parentheses
10a-(3(a-1))+2+2=0
We calculate terms in parentheses: -(3(a-1)), so:We add all the numbers together, and all the variables
3(a-1)
We multiply parentheses
3a-3
Back to the equation:
-(3a-3)
10a-(3a-3)+4=0
We get rid of parentheses
10a-3a+3+4=0
We add all the numbers together, and all the variables
7a+7=0
We move all terms containing a to the left, all other terms to the right
7a=-7
a=-7/7
a=-1
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