2(5b+1)-12=3(2b+12)-30

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Solution for 2(5b+1)-12=3(2b+12)-30 equation:



2(5b+1)-12=3(2b+12)-30
We move all terms to the left:
2(5b+1)-12-(3(2b+12)-30)=0
We multiply parentheses
10b-(3(2b+12)-30)+2-12=0
We calculate terms in parentheses: -(3(2b+12)-30), so:
3(2b+12)-30
We multiply parentheses
6b+36-30
We add all the numbers together, and all the variables
6b+6
Back to the equation:
-(6b+6)
We add all the numbers together, and all the variables
10b-(6b+6)-10=0
We get rid of parentheses
10b-6b-6-10=0
We add all the numbers together, and all the variables
4b-16=0
We move all terms containing b to the left, all other terms to the right
4b=16
b=16/4
b=4

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